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Class XII · Chemistry

Co-ordination Compounds: NEET MCQ practice

310 practice questions on Co-ordination Compounds, each with an explanation. Practise them chapter by chapter in the GyaanLoop app.

310

Practice questions

79

Easy

210

Medium

21

Hard

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What Co-ordination Compounds covers

Topics in the NEET (UG) 2026–27 syllabus for this chapter.

  • Introduction to coordination compounds, Werner's theory
  • Ligands, coordination number, denticity, chelation
  • IUPAC nomenclature of mononuclear coordination compounds, isomerism
  • Bonding- Valence Bond approach, basic ideas of Crystal Field Theory, colour and magnetic properties
  • Importance of coordination compounds in qualitative analysis, metal extraction, biological systems

Sample questions on Co-ordination Compounds

Try each one, then open the answer and explanation.

Question 1 · Practice question

[Ti (H₂O)₆] 3+ absorbs green and yellow region part of visible light. Then the transmitted colour of the compound is

  1. A.purple
  2. B.green
  3. C.blue
  4. D.red
Show answer

Answer: A. purple

The compound absorbs green and yellow light, so these colors are removed from white light. The remaining transmitted light is a mixture of red and blue, which appears purple. Students might pick red or blue individually, but these are only partial components; purple is the actual mixture seen as the complementary color.

Question 2 · Practice question

According to IUPAC nomenclature sodium nitroprusside dihydrate is named as

  1. A.Sodium pentacyanonitrosylferrate (III)
  2. B.Sodium nitroferrocyanide
  3. C.Sodium nitroferricyanide
  4. D.Sodium pentacyanonitrosylferrate (II)
Show answer

Answer: A. Sodium pentacyanonitrosylferrate (III)

The correct IUPAC name is sodium pentacyanonitrosylferrate(III) because the complex anion [Fe(CN)₅NO]²⁻ contains iron in +3 oxidation state, with five cyanide ligands and one nitrosyl ligand listed alphabetically. Option (b) and (c) are outdated trivial names, while (d) incorrectly states iron(II).

Question 3 · Practice question

In Fe(CO) 5, the Fe-C bond possesses:

  1. A.ionic character
  2. B.sigma character only
  3. C.pi character
  4. D.both sigma and pi characters
Show answer

Answer: D. both sigma and pi characters

In Fe(CO)₅, the Fe–C bond is a coordinate covalent bond formed by σ-donation of the lone pair from carbon to iron and π-backdonation from filled d orbitals of iron to empty antibonding π* orbitals of CO, giving both sigma and pi character. Options (a) and (b) are wrong because the bond is not ionic and not only sigma. Option (c) is incomplete as it ignores the sigma component.

Question 4 · Practice question

Number of compounds in which metal has zero oxidation state WO 3 ,Ni(CO) 4, MoO₃, Fe(CO) 5, Cr(CO) 6, [Pt(NH₃)₂CI₂], Co₂ (CO) 8 and Mn₂ (CO) 10

  1. A.5
  2. B.4
  3. C.1
  4. D.8
Show answer

Answer: A. 5

In metal carbonyls like Ni(CO)₄, Fe(CO)₅, Cr(CO)₆, Co₂(CO)₈, and Mn₂(CO)₁₀, the metal is in zero oxidation state because CO is a neutral ligand and the complexes are charge-neutral. In contrast, in WO₃ and MoO₃, oxygen is -2 so the metals are in +6 oxidation state; in [Pt(NH₃)₂Cl₂], Pt is in +2 oxidation state because Cl⁻ contributes -1 each. Students might mistakenly count Pt complex as zero if they forget to assign charges, but careful oxidation state assignment yields 5 compounds.

Question 5 · Practice question

Number of unpaired electrons in the complex [Ag(CN) 2 ] - are

  1. A.0
  2. B.1
  3. C.2
  4. D.4
Show answer

Answer: A. 0

Ag⁺ has a fully filled 4d¹⁰ configuration with all electrons paired, so the complex [Ag(CN)₂]⁻ has zero unpaired electrons. Students might incorrectly think about crystal field splitting, but even in any ligand field, d¹⁰ always gives diamagnetic species with no unpaired electrons.

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