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Class XII · Physics

Electromagnetic Induction and Alternating Currents: NEET MCQ practice

266 practice questions on Electromagnetic Induction and Alternating Currents, each with an explanation. Practise them chapter by chapter in the GyaanLoop app.

266

Practice questions

138

Easy

123

Medium

5

Hard

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What Electromagnetic Induction and Alternating Currents covers

Topics in the NEET (UG) 2026–27 syllabus for this chapter.

  • Electromagnetic induction, Faraday's law, induced emf and current, Lenz's law, eddy currents
  • Self and mutual inductance
  • Alternating current, peak and RMS value, reactance and impedance of LCR series circuit, resonance
  • Power in AC circuits, wattless current, AC generator and transformer

Sample questions on Electromagnetic Induction and Alternating Currents

Try each one, then open the answer and explanation.

Question 1 · Practice question

A pure resistance R, pure capacitance C and pure inductance L are connected in series and the impedance of the circuit at resonance is Z 0. If they are connected in parallel to each other, the maximum impedance at resonance will be:

  1. A.Less than R
  2. B.dependent on the values of C and L
  3. C.Equal to Z 0
  4. D.More than R
Show answer

Answer: C. Equal to Z 0

At resonance in a series RLC circuit, impedance is minimum and equals R, so Z₀=R. At resonance in a parallel RLC circuit, impedance is maximum and also equals R, because inductive and capacitive branch currents cancel, leaving only the resistive current. Thus both impedances are equal. Thought of as 'more than R'? No — it's exactly R.

Question 2 · Practice question

Find the series resonance frequency when L = 0.09 H, C = 25 F

  1. A.10.6 s -1
  2. B.0.106 s -1
  3. C.1.66 s -1
  4. D.1.06 s -1
Show answer

Answer: B. 0.106 s -1

At series resonance, the resonance frequency is f = 1/(2π√(LC)). Substituting L = 0.09 H and C = 25 F, we get f ≈ 0.106 Hz, which matches option B. The wrong option A (10.6 s⁻¹) might be a decimal error, while C (1.66 s⁻¹) arises if using ω = 1/√(LC) without dividing by 2π.

Question 3 · Practice question

Measure of sharpness in an ac circuit is given by

  1. A.Power ratio
  2. B.Quality factor
  3. C.Power factor
  4. D.Quality ratio
Show answer

Answer: B. Quality factor

The sharpness of resonance in an AC circuit is measured by the quality factor (Q-factor). It tells us how selective the circuit is to a particular frequency. Power factor (option C) is a different concept – it relates to the phase difference between voltage and current, not the sharpness of resonance.

Question 4 · Practice question

In a series RCL circuit at resonance the applied ac voltage is 220 V. The potential drop across the inductance is 110V, what is the potential drop across the capacitor?

  1. A.220 V
  2. B.220 √2 V
  3. C.110 √2 V
  4. D.110 V
Show answer

Answer: D. 110 V

At resonance in a series RLC circuit, the voltage across the inductor and the voltage across the capacitor are equal in magnitude because their reactances are equal (X(L) = X(C)). Since the voltage across the inductor is given as 110 V, the voltage across the capacitor must also be 110 V. The tempting wrong option of 220 V confuses the applied voltage across the entire circuit with the individual component voltages, which at resonance can be different from the total voltage.

Question 5 · Practice question

Acceptor circuit is

  1. A.When a series resonance circuit admits maximum current through it
  2. B.When a series resonance circuit admits minimum current through it
  3. C.When a series resonance circuit admits no current through it
  4. D.Both b and c
Show answer

Answer: A. When a series resonance circuit admits maximum current through it

An acceptor circuit is another name for a series LCR circuit at resonance, where impedance is minimum and current is maximum. It 'accepts' the signal strongly at the resonant frequency. Options (b) and (c) are incorrect because at resonance current is maximum, not minimum or zero.

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