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Class XI · Physics

Kinematics: NEET MCQ practice

418 practice questions on Kinematics, each with an explanation. Practise them chapter by chapter in the GyaanLoop app.

418

Practice questions

230

Easy

176

Medium

12

Hard

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What Kinematics covers

Topics in the NEET (UG) 2026–27 syllabus for this chapter.

  • Frame of reference, motion in a straight line
  • Uniform and non-uniform motion, average and instantaneous velocity/acceleration
  • Scalars and vectors, vector addition and subtraction
  • Relative velocity, motion in a plane, projectile motion
  • Uniform circular motion

Sample questions on Kinematics

Try each one, then open the answer and explanation.

Question 1 · Practice question

A body moves 6 m north. 8 m east and 10 m vertically upwards, what is its resultant displacement from initial position is

  1. A.10√2 m
  2. B.10 m
  3. C.10/√2 m
  4. D.20 m
Show answer

Answer: A. 10√2 m

Since the three displacements are perpendicular (north, east, upwards), the resultant displacement is the diagonal of a cuboid with sides 6 m, 8 m, and 10 m. Its magnitude is √(6² + 8² + 10²) = √(36+64+100) = √200 = 10√2 m. The tempting wrong option (b) 10 m would be the distance if only the vertical displacement mattered, but vector addition requires combining all three components.

Question 2 · Practice question

Which of the following is true regarding projectile motion?

  1. A.Horizontal velocity of projectile is constant
  2. B.Vertical velocity of projectile is constant
  3. C.Acceleration is not constant
  4. D.Momentum is constant
Show answer

Answer: A. Horizontal velocity of projectile is constant

In projectile motion, horizontal velocity remains constant because there’s no acceleration in the horizontal direction (ignoring air resistance). The vertical velocity changes due to gravity, acceleration is constant (g downward), and momentum changes because velocity changes.

Question 3 · Practice question

A bomb is released by a horizontal flying aeroplane. The trajectory of the bomb is

  1. A.a parabola
  2. B.a straight line
  3. C.a circle
  4. D.a hyperbola
Show answer

Answer: A. a parabola

When a bomb is released horizontally from a moving plane, it has an initial horizontal velocity and is acted upon by gravity, which gives it a vertical acceleration. The combination of uniform horizontal motion and uniformly accelerated vertical motion results in a parabolic trajectory. The other options are wrong: a straight line would occur only if there were no gravity, while circular or hyperbolic paths require different force conditions not present here.

Question 4 · Practice question

In case of a projectile motion, what is the angle between the velocity and acceleration at the highest point?

  1. A.0°
  2. B.45°
  3. C.90°
  4. D.180°
Show answer

Answer: C. 90°

At the highest point of projectile motion, velocity is horizontal (only horizontal component remains) and acceleration due to gravity is always vertical downward. The angle between horizontal and vertical is 90°. The common mistake is to think acceleration is zero or along the velocity direction, but gravity always acts downward regardless of position.

Question 5 · Practice question

If a body is projected with an angle θ to the horizontal, then

  1. A.Its velocity is always perpendicular to its acceleration.
  2. B.Its velocity becomes zero at its maximum height.
  3. C.Its velocity makes zero angle with the horizontal at its maximum height.
  4. D.The body just before hitting the ground, the direction of velocity coincides with the acceleration.
Show answer

Answer: C. Its velocity makes zero angle with the horizontal at its maximum height.

At maximum height, the vertical component of velocity becomes zero, leaving only the horizontal component. Therefore, velocity is purely horizontal and makes zero angle with the horizontal, making option (c) correct. Option (a) is tempting because acceleration is always downward, but velocity is perpendicular only at the highest point; option (b) is wrong because horizontal velocity never vanishes in ideal projectile motion; option (d) confuses velocity direction at impact with vertical acceleration.

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