Class XII · Physics
Atoms and Nuclei: NEET MCQ practice
200 practice questions on Atoms and Nuclei, each with an explanation. Practise them chapter by chapter in the GyaanLoop app.
200
Practice questions
128
Easy
67
Medium
5
Hard
What Atoms and Nuclei covers
Topics in the NEET (UG) 2026–27 syllabus for this chapter.
- Alpha-particle scattering experiment, Rutherford's model of atom
- Bohr model, energy levels, hydrogen spectrum
- Composition and size of nucleus, atomic masses, isotopes
- Mass-energy relation, mass defect, binding energy per nucleon and its variation with mass number
- Nuclear fission and fusion
Sample questions on Atoms and Nuclei
Try each one, then open the answer and explanation.
Question 1 · Practice question
Suppose potential energy between particle A and B at separation r is given by U = k ln r, where k is constant. For such hypothetical system, the ratio of energy difference between energy levels (n = 1 and n = 2) and (n = 2 and n = 4) is (The energy of a particle in n th level is –13.6/n 2 )
- A.1
- B.2
- C.1/2
- D.3
Show answer
Answer: A. 1
In the given system U = k ln r, force F = –dU/dr = –k/r. Using Bohr quantization mvr = nħ and force condition mv²/r = k/r, velocity is constant, radius rₙ ∝ n, so potential energy Uₙ = k ln n + constant. Hence energy Eₙ = constant + k ln n, and energy differences like ΔE₁₂ = k ln 2, ΔE₂₄ = k ln 2, giving ratio 1. The mention of –13.6/n² is a distractor; applying it gives ratio 4, which is not among the options.
Question 2 · Practice question
Q. In a crystal, the distance between two atoms is:
- A.A. 200 Å to 300 Å
- B.B. 2 Å to 3 micron
- C.C. 2 Å to 3 Å
- D.D. 2 mm to 3 mm
Show answer
Answer: C. C. 2 Å to 3 Å
In crystals, the typical separation between neighboring atoms is 2–3 Å (1 Å = 10⁻¹⁰ m), a standard recall from atomic sizes and crystal lattices. Options with 200–300 Å, microns, or millimeters are far too large — those correspond to macroscopic distances or larger structures, not interatomic spacing.
Question 3 · Practice question
Q. The maximum possible electrons in an orbit is:
- A.A. 8 (2s + 6p electrons)
- B.B. 8 (6s + 2p electrons)
- C.C. 8 (4s + 4p electrons)
- D.D. 8 (1s + 7p electrons)
Show answer
Answer: A. A. 8 (2s + 6p electrons)
For the second shell (n = 2), s subshell holds max 2 electrons and p subshell holds max 6 electrons, giving a total of 8 electrons — matching option A. The wrong options incorrectly assign more than 2 electrons to an s subshell or fewer than 6 to a full p subshell, violating the rules of electron capacity per subshell.
Question 4 · Practice question
Radioactive material has a half-life of 10 days. What fraction of the material would remain after 30 days?
- A.0.5
- B.0.25
- C.0.125
- D.0.33
Show answer
Answer: C. 0.125
Every 10 days, half the material decays, so after 30 days (3 half-lives), fraction remaining = (1/2)³ = 1/8 = 0.125. Option B (0.25) corresponds to 2 half-lives, and option A (0.5) is only 1 half-life — those come from mis-counting the number of half-lives.
Question 5 · Practice question
Which energy state of triply ionized beryllium (Be +++ ) has the same electron orbital radius as that of the ground state of hydrogen? Given Z for beryllium = 4
- A.n = 1
- B.n = 2
- C.n = 3
- D.n = 4
Show answer
Answer: B. n = 2
The Bohr radius formula r ∝ n²/Z shows that for hydrogen (Z=1, n=1) radius is a₀. For Be³⁺ (Z=4), setting n²/4 = 1 gives n=2. The ground‑state hydrogen radius is matched by the n=2 state of Be³⁺. Avoid choosing n=1 because smaller Z in denominator would give a smaller radius.
More Class XII Physics chapters
- Electrostatics379 questions
- Current Electricity204 questions
- Magnetic Effects of Current and Magnetism286 questions
- Electromagnetic Induction and Alternating Currents266 questions
- Electromagnetic Waves110 questions
- Optics413 questions